Quadratic sequences

Tier: #Higher

🔗What you need to know first
How to

A quadratic sequence has a constant second difference (the differences of the differences are equal). The $n$th term contains an $n^2$ term.

Method to find the $n$th term:

  1. Find the first and second differences
  2. The coefficient of $n^2$ is half the second difference
  3. Subtract the $an^2$ sequence from the original to get a linear remainder
  4. Find the $n$th term of the linear part

Example: Sequence: 3, 8, 15, 24, 35, …

  • First differences: 5, 7, 9, 11 — not constant
  • Second differences: 2, 2, 2 — constant → coefficient of $n^2 = \frac{2}{2} = 1$
  • Subtract $n^2$ sequence (1, 4, 9, 16, 25): remainders are 2, 4, 6, 8, 10 → $n$th term is $2n$
  • Full $n$th term: $n^2 + 2n$

Check: when $n=1$: $1+2=3$ ✓

Common error: forgetting to halve the second difference when finding the $n^2$ coefficient.

Questions to practise

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📝Past paper questions
💬What the examiners say
  • "Students would be wise to check their answers to questions of this type by substitution."
⬆️How you can quickly improve
  • Find the second differences, halve them to get the n² coefficient, subtract the n² values from the original sequence to get a linear sequence, then find the linear nth term and add it to the n² part.
  • Always verify by substituting n = 1 and n = 2 — if the values don't match, check the signs in your linear part.
  • For 'when do two sequences first match' questions, generate terms of both and look for matching values — algebra isn't always the right tool here.
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