Equation of a circle

Tier: #Higher

🔗What you need to know first
How to

A circle centred at the origin with radius $r$ has equation: $$x^2 + y^2 = r^2$$

A circle centred at point $(a, b)$ with radius $r$ has equation: $$(x - a)^2 + (y - b)^2 = r^2$$

Example: A circle with centre $(3, -2)$ and radius 5: $$(x - 3)^2 + (y + 2)^2 = 25$$

Finding the radius and centre from an equation: compare with the standard form. $$x^2 + y^2 = 49 \implies \text{centre } (0,0), \text{ radius } 7$$

Tangent to a circle: a tangent at point $(x_1, y_1)$ on circle $x^2 + y^2 = r^2$ is: $$x\cdot x_1 + y\cdot y_1 = r^2$$

The tangent is perpendicular to the radius at the point of contact.

Common error: writing $(x + a)^2 + (y + b)^2 = r^2$ for centre $(a, b)$ — remember the signs flip.

Questions to practise

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📝Past paper questions
💬What the examiners say
  • "Learners should be encouraged to sketch the circle and tangent in questions like this as showing the key values could help them find the gradients of the radius and the tangent."
  • "To improve performance, learners should develop a secure understanding of the geometric relationship between tangents and circles, specifically that the radius meets the tangent at a right angle and that the point of contact lies on both the circle and the tangent line."
⬆️How you can quickly improve
  • When substituting an expression into a squared term, always write the bracket first: use (3p)², not 3p².
  • Write out the centre and radius explicitly from the equation before any other work: 'centre = (a, b), radius = √r²'.
  • For a tangent at a given point, find the gradient of the radius to that point, then take the negative reciprocal to get the tangent's gradient.
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