Quadratic inequalities

Tier: #Higher

🔗What you need to know first
How to

A quadratic inequality involves an expression like $x^2 + bx + c > 0$ or $< 0$. Solve it by finding the roots and then interpreting the parabola.

Method:

  1. Solve the corresponding equation (set equal to zero) to find the critical values
  2. Sketch the parabola (or consider its shape — $x^2$ coefficient positive means U-shape)
  3. Identify the regions where the parabola is above or below the $x$-axis

Example: Solve $x^2 - 5x + 6 < 0$ $$x^2 - 5x + 6 = 0 \implies (x-2)(x-3) = 0 \implies x = 2 \text{ or } x = 3$$ The parabola is U-shaped, so it is below the $x$-axis between the roots: $$\boxed{2 < x < 3}$$

For $x^2 - 5x + 6 > 0$: the answer is $x < 2$ or $x > 3$ (two separate regions).

Common error: writing the answer as a single inequality like $2 < x < 3$ when it should be two separate inequalities (for the $>$ case).

Questions to practise

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📝Past paper questions
💬What the examiners say
  • "The best answers demonstrated a very good understanding of the topic together with the good practice of including a graph sketch with the rest of their working."
  • "A diagram — either a number line or a sketch of the quadratic — helps you identify the regions that satisfy each inequality. To score the final mark, you must state both linear inequalities that satisfy both quadratic inequalities."
⬆️How you can quickly improve
  • After finding the critical values, sketch the parabola and mark the roots — use the shape of the curve to work out which region satisfies the inequality.
  • Write the solution as an inequality, not an equation — the answer is a range of values, not specific points.
  • Extract critical values carefully from the factorised form: (x − a) = 0 gives x = a, and (x + b) = 0 gives x = −b — write each step explicitly.
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